<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: While fishing, you get bored and start to swing a sinker weight around in a circle below you on a 0.23 m piece</title>
	<atom:link href="http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php/feed" rel="self" type="application/rss+xml" />
	<link>http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php</link>
	<description>Hot Fishing Items At The Best Prices</description>
	<lastBuildDate>Tue, 20 Jan 2009 23:00:32 -0500</lastBuildDate>
	<generator>http://wordpress.org/?v=2.8.4</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: ukmudgal</title>
		<link>http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php/comment-page-1#comment-264</link>
		<dc:creator>ukmudgal</dc:creator>
		<pubDate>Tue, 02 Dec 2008 09:25:31 +0000</pubDate>
		<guid isPermaLink="false">http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php#comment-264</guid>
		<description>length of fishing line 0.23 m  is  hypoteneus of right angelled triangle in vertical plane with base equal to radius &#039;r&#039; of circle

Suppose  in the vector triangle  of forces, fishing line length Lrepresents tension in the line

If  height &#039;h&#039; of triangle represents weight &#039;mg&#039; of sinker and base &#039;r&#039;  of triangle represents  centripetal force F=mv^/r=mr*4*(pi)^2 / T^2

where T is time period =0.60  s

mg/h=mr4(pi)^2/rT^2

h=gT^2/4(pi^2)=9.8*0.6*0.6 / 4*9.87= 0.089 m

suppose fishing line makes angle O with vertical ,then

cosO=h/ L( lenght of line) 

cosO=0.089/0.23=0.3885

O=67.13 degree

Angle O with vertical is 67.13 degree</description>
		<content:encoded><![CDATA[<p>length of fishing line 0.23 m  is  hypoteneus of right angelled triangle in vertical plane with base equal to radius &#8216;r&#8217; of circle</p>
<p>Suppose  in the vector triangle  of forces, fishing line length Lrepresents tension in the line</p>
<p>If  height &#8216;h&#8217; of triangle represents weight &#8216;mg&#8217; of sinker and base &#8216;r&#8217;  of triangle represents  centripetal force F=mv^/r=mr*4*(pi)^2 / T^2</p>
<p>where T is time period =0.60  s</p>
<p>mg/h=mr4(pi)^2/rT^2</p>
<p>h=gT^2/4(pi^2)=9.8*0.6*0.6 / 4*9.87= 0.089 m</p>
<p>suppose fishing line makes angle O with vertical ,then</p>
<p>cosO=h/ L( lenght of line) </p>
<p>cosO=0.089/0.23=0.3885</p>
<p>O=67.13 degree</p>
<p>Angle O with vertical is 67.13 degree</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Jerry BO</title>
		<link>http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php/comment-page-1#comment-263</link>
		<dc:creator>Jerry BO</dc:creator>
		<pubDate>Mon, 01 Dec 2008 20:52:54 +0000</pubDate>
		<guid isPermaLink="false">http://thelazyfisherman.net/fishing-talk/while-fishing-you-get-bored-and-start-to-swing-a-sinker-weight-around-in-a-circle-below-you-on-a-023-m-piece-2.php#comment-263</guid>
		<description>It wouldn&#039;t be vertical. It would be &quot;diagonal.&quot; and that is why
I would never have you in a boat with me, because, I would
end up with that hook in my eye. </description>
		<content:encoded><![CDATA[<p>It wouldn&#8217;t be vertical. It would be &#8220;diagonal.&#8221; and that is why<br />
I would never have you in a boat with me, because, I would<br />
end up with that hook in my eye.</p>
]]></content:encoded>
	</item>
</channel>
</rss>
